EXPT NO: 2. USE OF MICROMETER SCREW GAUGE
Aim : To measure cross sectional area of uniform
wire and the thickness of plate.
Apparatus : Micrometer screw gauge,
plate, a metal wire of uniform diameter.
Diagram :

Screw
Gauge

Formula : Pitch of micrometer screw gauge.

Least count of micrometer screw gauge.
Procedure : To
find the least count of screw gauge :
·
Note the value of the
smallest division on main scale of screw gauge.
·
Coincide the zero of
circular scale with reference line and note the main scale reading.
·
Rotate the screw to
complete 5 full rotations. Again note down the main scale reading.
·
The difference between
these two main scale readings gives the distance covered by the screw tip in 5
rotations. Then calculate pitch of micrometer screw gauge.
·
Then, note down the total
number of divisions of circular scale (N)
·
Finally, calculate least
count of the micrometer screw gauge.
:To find the zero error :
·
Bring the two jaws of gauge
in contact with each other.
·
Observe and conclude
according to the following given conditions.
·
If zero of circular scale
coincides with reference line.
There is no zero error. (Z) = 0
·
If zero of circular scale
is below reference line. If nth division of circular scale coincides with
reference line.
There is Positive error (Z) =
+ (n x L.C)
·
If zero of circular scale
is above the reference line. If nth
division of circular scale coincides with reference line and N is total number
of division on circular scale.
There is negative error (Z) = [(N - n) x L.C.]
:To determine the diameter of wire :
Hold the wire between the jaws of
micrometer and note down the following :
Find the thickness of plate in similar manner.
Observations:
Number of rotations to screw n =………………..
Distance advanced by screw in N rotations X =………………..
Pitch of the screw (P = X/n) P =………………..
Total number of divisions on the circular scale N =………………..
Least count of screw gauge L.C=(P/N)
=………………..
Zero error (positive/negative) Z =………………..
Observation Table :
Diameter of the wire / thickness of the
plate.
|
Object
|
Obs No
|
Dimension
|
Main Scale reading
A cm
|
Circular
Scale reading B
|
Total reading C=A+(BxL.C)
|
Corrected reading T=C+Z cm
|
Mean
reading cm
|
|
Wire
|
01
|
Diameter
|
|
|
|
|
|
|
02
|
|
|
|
|
|
||
|
03
|
|
|
|
|
|
||
|
Plate
|
01
|
Thickness
|
|
|
|
|
|
|
02
|
|
|
|
|
|
||
|
03
|
|
|
|
|
|
Calculations :
Least Count :
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|
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Results : i) Cross sectional Area =…………..cm2
ii) Thickness of Plate =……………..cm
Precautions :
J K L

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