Pages

12


EXPT NO: 12. OHM'S LAW
Aim :        To determine resistance per cm of a given wire by plotting a graph of potential difference versus current.
Apparatus : Uniform metal wire of unknown resistance, voltmeter, ammeter, battery  power supply, rheostat, meter scale, one way key, connecting wires etc.
Circuit Diagram :
Formulae: Résistance of wire                                  
                                    Resistance per cm of a wire = 
Procedure :
*      Arrange the apparatus as shown in the circuit diagram and make the connections.
*      Determine the least count of voltmeter and ammeter.
*      Close the key (K) and adjust the rheostat, such that a minimum current passes through the resistance wire. Note down potential difference (V) and corresponding current (I)
*      Repeat the above step for different values (V) and corresponding current (I).
*      Calculate the resistance in each case.
*      Plot the graph of V versus I. Determine the slope of a graph, which is the resistance (R) of wire.
Observations :1)         Length of a given wire = L = …………cm
2)         Least count of ammeter = …………mA
3)         Least count of voltmeter = …………V
To determine resistance of wire (R).
            Sr.No.
Current I
(mA)
Current  I
(A)
Potential V
(volt)
Resistance  
Mean Resistance
 R  
01





02




03




04




05





Calculations :
Obs No
01
02
03
04
05
logV=a





logI=b





a-b=c





R=antilog c










Graph:

Result:
1)         Unknown Resistance of the wire by calculation        =…………..
2)         Unknown Resistance of the wire by Graph    =…………..
3)         Resistance per cm of the wire by calculation =…………..
4)         Resistance per cm  of the wire by Graph                   =…………..
Precautions : 
1)                  The connection should be neat and tight .
2)                  The key should be inserted only while taking the observation to avoid the heating of resistance.
3)                  If the deflection of the pointer is in between the two division then adjust the rheostat such that the reading should be exactly coincides with the division.
J K L

No comments:

Post a Comment